question

Triangles A Q R and A K P share point A.
Triangle A Q R is rotated up and to the right for form triangle A Q R.
Which rigid transformation would map Î”AQR to Î”AKP?
a rotation about point A
a reflection across the line containing AR
a reflection across the line containing AQ
a rotation about point R

answer

A

question

Triangles RQS and NTV have the following characteristics: â€¢ Right angles at âˆ Q and âˆ T â€¢ RQ â‰… NT
Can it be concluded that Î”RQS â‰… Î”NTV by SAS? Why or why not? Yes, one set of corresponding sides and one corresponding angle are congruent.
Yes, they are both right triangles.
No, it is necessary to know that another set of corresponding sides is congruent.
No, it is not possible for the triangles to be congruent.

answer

C

**Explanation:** The two triangles can be concluded to be congruent by the Side-Angle-Side (SAS) Congruence Theorem. This theorem states that if two sides and the angle between them of one triangle are congruent to two sides and the angle between them of another triangle, then the two triangles are congruent. In this case, the sides RQ and NT are congruent, as well as the angle between them (the right angle at Q and T), so the two triangles are congruent.

question

Which of these triangle pairs can be mapped to each other using a single translation?
A.Triangles C E D and C N P are congruent. Triangle C E D is rotated about point C and then reflected across a line to form triangle C N P. B.Triangles C N E and C E D are congruent. Triangle C N E is reflected across a line and then rotated slightly to form triangle C E D.
C.Triangles C E D and M D P are congruent. Triangle M D P is rotated and shifted up to form triangle C E D.
D.Triangles C E D and M P N are congruent. Triangle C E D is shifted to the right to form triangle M P N. Mark this and return

answer

D

**Explanation:** to question.Triangles C E D and M P N can be mapped to each other using a single translation.

question

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K. Two rigid transformations are used to map Î”HJK to Î”LMN. The first is a translation of vertex H to vertex L.
What is the second transformation?
a reflection across the line containing HK
a rotation about point H
a reflection across the line containing HJ
a rotation about point K

answer

B

**Explanation:** The second transformation is a reflection across the line containing HK.

question

The proof that Î”EFG â‰… Î”JHG is shown. Given: G is the midpoint of HF, EF âˆ¥ HJ, and EF â‰… HJ. Prove: Î”EFG â‰… Î”JHG Triangles E F G and J H G share common point G. Statement Reason 1. G is the midpoint of HF 1. given 2. FG â‰… HG 2. def. of midpoint 3. EF âˆ¥ HJ 3. given 4. ? 4. alt. int. angles are congruent 5. EF â‰… HJ 5. given 6. Î”EFG â‰… Î”JHG 6. SAS
What is the missing statement in the proof?
âˆ FEG â‰… âˆ HJG
âˆ GFE â‰… âˆ GHJ
âˆ EGF â‰… âˆ JGH
âˆ GEF â‰… âˆ JHG

answer

B

question

Which of these triangle pairs can be mapped to each other using both a translation and a rotation about C?
Triangles X Y C and A B C are shown. Both triangles are congruent and share common point C. Triangle A B C is slightly lower than triangle X Y C.
Triangles X Y Z and A B C are shown. Both triangles are congruent. Triangle X Y Z is identical to triangle A B C but is slightly higher. Triangles X Y Z and A B C are shown. Both triangles are congruent. Triangle X Y Z is reflected across a line to form triangle A B C. Triangles X Y Z and A B C are shown. Both triangles are congruent. Triangle X Y Z is rotated down and to the left to form triangle A B C. It is also slightly higher than triangle A B C.

answer

D

**Explanation:** The first and third pairs of triangles can be mapped to each other using both a translation and a rotation about C. The second pair of triangles can be mapped to each other using a translation, but not a rotation about C.

question

Triangles H J K and L M N are congruent. Triangle H J K is rotated about point H to form triangle L N M. Triangle L M N is higher than triangle H J K.
How can a translation and a rotation be used to map Î”HJK to Î”LMN? Translate H to L and rotate about H until HK lies on the line containing LM.
Translate K to M and rotate about K until HK lies on the line containing LM.
Translate K to N and rotate about K until HK lies on the line containing LN.
Translate H to N and rotate about H until HK lies on the line containing LN.

answer

C

question

Triangles J K L and M N R are shown.
In the diagram, KL â‰… NR and JL â‰… MR.
What additional information is needed to show Î”JKL â‰… Î”MNR by SAS?
âˆ J â‰… âˆ M
âˆ L â‰… âˆ R
âˆ K â‰… âˆ N
âˆ R â‰… âˆ K

answer

B

question

Triangles A B C and X Y Z is congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C. Triangle A B C is reflected across a line to form triangle X Y Z.
Two rigid transformations are used to map Î”ABC to Î”XYZ. The first is a translation of vertex A to vertex X. What is the second transformation?
a reflection across the line containing line AB
a reflection across the line containing line AC
a rotation about point A
a rotation about point B

answer

A

**Explanation:** The second transformation is a reflection across the line containing line AB.

question

The proof that Î”MNS is congruent to Î”QNS is shown. Given: Î”MNQ is isosceles with base , and and bisect each other at S. Prove: Square M N Q R is shown with point S in the middle. Lines are drawn from each point of the square to point S to form 4 triangles.
We know that Î”MNQ is isosceles with base. So, by the definition of isosceles triangle. The base angles of the isosceles triangle, and , are congruent by the isosceles triangle theorem. It is also given that and bisect each other at S. Segments _______ are therefore congruent by the definition of bisector. Thus, by SAS.
NS and QS
NS and RS
MS and RS
MS and QS

answer

D