Genetics Test 3 Mastering Questions

6 September 2022
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question
True or False: A bacterial strain that is pro+ thi+ leu- met- will grow on minimal media plus leucine and thiamine.
answer
False: It can not synthesize leu and met.
question
Which of the following statements about conjugation is true? A. Only competent cells can undergo conjugation B. DNA is transferred from an F+ cell to an F- cell. C. One strand of DNA from an F+ cell integrates into the chromosome of an F- cell, and the other strand is degraded. D. The F factor is an element that is found in the chromosome of an F+ cell.
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B.DNA is transferred from an F+ cell to an F- cell
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How is a merozygote formed?
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The F factor and several adjacent genes are excised from the chromosome of an Hfr cell and transferred to an F- strain.
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In an interrupted mating experiment, the purpose of plating cells on a selective medium is___________.
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To ensure that only recombinant genotypes are recovered.
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Mapping bacterial genes by conjugation is based on which of the following assumptions? A. Genes are transferred from donor to recipient in a linear fashion B. F minus bacterial strains are capable of transferring genes to Hfr strains C. Conjugation is not disrupted when a bacterial culture is mixed in a blender D. Bacterial cells are capable of growing in the presence of sodium azide.
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A. Genes are transferred from donor to recipient in a linear fashion
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Which of the following statements about mapping bacterial genes by conjugation is NOT true? A. For any two genes transferred from donor to recipient, all genes reside between them have also been transferred. B. It is necessary that all Hfr cells be absent from the population of cells recovered for genotyping C. The closer a gene to the Hfr origin, the more likely it will be transferred to the recipient during conjugation. D. Two genes that are very close together may appear to be transferred at the same time.
answer
C. The closer a gene to the Hfr origin, the more likely it will be transferred to the recipient during conjugation
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Order the following steps of bacterial transformation: 1. One strand of the donor cell DNA is degraded 2. Transformed DNA recombines withe the recipient cells chromosome. 3.Donor cell DNA binds to a receptor site on the recipient cell. 4. Transformed DNA pairs with homologous region on the recipient cell chromosome 5. Donor cell lyses, releasing pieces of its chromosome into the environment.
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5, 3, 1, 4, 2
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True or false: Guanine and adenine are purines found in DNA
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True
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Which of the following statements about DNA structure is true: A. The pentose sugar in DNA is ribose B. The nucleic acid strands in a DNA molecule are oriented antiparallel to each other, meaning they run in opposite directions C. Hydrogen bonds formed between the sugar-phosphate backbones of the DNA chains helps to stabilize DNA structure D. Nucleic acids are formed through phosphodiester bonds that link nucleosides together
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B. The nucleic acid strands in a DNA molecule are oriented antiparallel to each other, meaning they run in opposite directions
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What is the complementary DNA sequence to 5' ATGCTTGACTG 3'?
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5' CAGTCAAGCAT 3'
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Complementary sequence for 3' ATTGCAGTACC 5' DNA sequence (going 5' to 3').
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5' TAACGTCATGG 3'
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The Hershey and Chase experiments involved the preparation of the two different types of radioactively labeled phages. Why were these two different preparations required?
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To label the two phage requirements, DNA and protein. This allowed them to be identified at the end of the experiment.
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What was the main conclusion of the Hershey-Chase experiment?
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DNA is the identity of the hereditary material in phage T2.
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Which of the following outcomes would be most likely if the Hershey-Chase experiments were repeated without the step involving the blender? A. Neither preparations of infected bacteria would exhibit radioactivity B. The phage would fail to infect bacteria C. Both preparations of infected bacteria would contain both P32 and S35 D. Both preparations of infected bacteria would exhibit radioactivity
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D. Both preparations of infected bacteria would exhibit radioactivity.
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What did Frederick Griffith establish in his 1928 experiment?
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Heat-killed bacteria harbor the constituents necessary to convey genetic properties to living bacteria.
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To be certain that the extract prepared from virulent cells still contained the transforming principle that was present prior to lysis, Avery did what?
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Incubated nonvirulent cells with the complete extract.
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How many OH's does a ribose have?
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Three
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How many OH's does a deoxyribose have?
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Two
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Where is deoxyribose present?
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DNA
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Where is ribose present?
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RNA
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After replication is complete, the strand of new DNA, called ____________, is complementary to the parental strand.
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Daughter DNA
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The new strand that grows continuously in the 5' to 3' direction is called the ___________.
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Leading strand
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____________ are the short sections of DNA that are synthesized on the lagging strand of the replicating DNA.
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Okazaki fragments
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During DNA replication, an open section of DNA, in which a DNA polymerase can replicate DNA, is called a ________________.
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Replication fork
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The enzyme that can replicate DNA is called ________________.
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DNA polymerase
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What end of the DNA strand is the phosphate group on? (5' or 3')
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5'
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What end of the DNA molecule is the OH group on? (5' or 3')
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3'
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This enzyme: -Binds ahead of the replication fork -Breaks covalent bonds in the DNA backbone
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Topoisomerase
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This enzyme: -Prevents H-bonds between bases -Binds after the replication fork
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Single-stranded binding protein
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This molecule: -Breaks H-bonds between bases -Binds at the replication fork
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Helicase
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What would happen if the single-stranded binding protein was nonfunctional?
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DNA strands would not remain separated; single strands would become double-stranded DNA
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What would happen if primase was nonfunctional?
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RNA primers would not form; DNA polymerase III could not synthesize DNA
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What would happen if helicase was nonfunctional?
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DNA strand would not separate.
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What would happen if topoisomerase was nonfunctional?
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DNA would become tangled downstream of the replication fork; replication may start, but would stop when it reaches the tangled DNA.
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What would happen if DNA polymerase I was nonfunctional?
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RNA primers would not be removed efficiently and would not be replaced with DNA nucleotides
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What would happen if DNA ligase was nonfunctional?
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Nicks would remain in the phosphodiester backbone of the DNA molecule
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What would happen if DNA polymerase III was nonfunctional?
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Replication fork would form normally, but new DNA would not be synthesized.
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True or False: In contrast with euchromatin, heterochromatin contains more genes and is earlier replicating.
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False
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What makes up the protein component of a nucleosome?
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Two tetramers of histone proteins.
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What is the first order of chromatin packing?
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DNA coiling around nucleosomes
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True or False: The second order of chromatin packing occurs when nucleosomes coil together to form a fiber that is 300 nm in diameter.
answer
False: the second order is nucleosomes coiling together to form a solenoid fiber that is 30 nm in diameter.
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Eukaryotic chromosomes contain two general domains that relate to the degree of condensation. These two regions are ______________.
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Heterochromatin and euchromatin
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Viral genomes and eukaryotic genomes are similar in which of the following ways? A. Their nucleic acid may be single stranded or double stranded B. There are few, if any, DNA-binding proteins C. They have the ability to pack a genome into a small volume D. They are unable to replicate their own DNA
answer
C. They have the ability to pack a genome into a small volume
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Rank the following levels of chromatin compaction in eukaryotes from the most to least compact: 1. Chromatid 2. Solenoid 3. Naked DNA 4. Loop domain 5. Metaphase chromosome 6. Nucleosome
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3, 6, 2, 4, 1, 5
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Which histone helps stabilize the solenoid structure?
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H1
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Histone acetyltransferases (HATs) are capable of remodeling chromatin by adding acetyl groups to various lysine residues in histones that comprise the nucleosome. Following this modification, the lysine residue no longer has a positive charge. Which statement is true? A.Histones in general have a net positive charge that allow them to bind to DNA. Acetylation of histones, decreases their positive charge and strengthens the histone-DNA interaction. B.Histones in general have a net negative charge that allow them to bind to DNA. Acetylation of histones, decreases their positive charge and weakens the histone-DNA interaction. C. Histones in general have a net negative charge that allow them to bind to DNA. Acetylation of histones, decreases their positive charge and strengthens the histone-DNA interaction
answer
D. Histones in general have a net positive charge that allow them to bind to DNA. Acetylation of histones, decreases their positive charge and weakens the histone-DNA interaction.