question

A simple CPM network has five activities, A, B, C, D, and E. A is an immediate predecessor of C and of D. B is also an immediate predecessor of C and of D. C and D are both immediate predecessors of E. Given the above scenario, which of the following is correct?

answer

There are four paths in this network.

question

Which of these statements regarding time-cost tradeoffs in CPM networks is true?

answer

Crashing shortens the project duration by assigning more resources to one or more of the critical tasks.

question

With respect to PERT and CPM, slack__________

answer

is the amount of time a task may be delayed without changing the overall project completion time.

question

The critical path for the network activities shown below is _______ with duration _______.
Activity
Duration
Immediate Predecessors
A
4
B
2
A
C
7
D
4
A
E
5
B,C,D

answer

A-D-E; 13

question

The three phases involved in the management of large projects are:

answer

Planning, scheduling, and controlling

question

An activity on a PERT network has these time estimates: optimistic = 1, most likely = 2, and pessimistic = 5. Its expected time is:

answer

2.33

question

The critical path of a network is the__________

answer

longest time path through the network.

question

Dummy activities__________

answer

are used when two activities have identical starting and ending events.

question

With respect to PERT and CPM, slack is the amount of time a task may be delayed without changing the overall project completion time.

answer

Latest start is the term used to describe the latest time an activity can be started without delaying the entire project. Latest finish is the term used to describe the latest time an activity can be completed and not delay the completion time of the entire project.
previous

question

Which of the following is a basic assumption of PERT?

answer

No activity in the network must be repeated.

question

The critical path for the network activities shown below is A-D-E with duration 13. Critical path activities are those activities that will delay the entire project if they are not completed on time. In this case, activity A is an immediate predecessor for A and D and the final activity is E. The sum of the duration for this network is 13 (4+4+5 = 13).

answer

2.33

question

Expected time (t) is calculated using the following formula: t = (a + 4m + b)/6, where
a = optimistic time estimate (in this case 1); m = most likely time estimate (in this case 2); and b = pessimistic time estimate (in this case 5). Therefore;

answer

An activity on a PERT network has these time estimates: optimistic = 1, most likely = 2, and pessimistic = 5. Its expected time is:
t = (1 + 4*2 + 5)/6
t = 14/6
t = 2.33

question

An activity has an optimistic time of 15 days, a most likely time of 18 days, and a pessimistic time of 27 days. What is the expected time?

answer

19 days

question

Which of the following is determined during the forward pass?

answer

Early start

question

An activity on a PERT network has these time estimates: optimistic = 2, most likely = 5, and pessimistic = 10. Its expected time is:

answer

5.33

question

An activity on a PERT network has these time estimates: optimistic =2, most likely = 3, and pessimistic 8. Its expected time and variance (if it is a critical activity) are:

answer

3.67 and 1

question

Which of the following statements regarding PERT analysis is true?

answer

Only critical activities contribute to the project variances.

question

PERT analysis computes the variance of the total project completion time as:

answer

The sum of all variances of all activities on the critical path

question

Expected time (t) is calculated using the following formula: t = (a + 4m + b) / 6, where
a = optimistic time estimate (in this case 2); m = most likely time estimate (in this case 3); and b = pessimistic time estimate (in this case 8). Therefore;
t = (2 + 4*3 + 8) / 6
t = 22 / 6
t = 3.67

answer

Variance (v) is calculated using the following formula: v = [(b-a) / 6]2, where b= pessimistic time estimate (in this case 8) and a = optimistic time estimate (in this case 2). Therefore;
v = [(b-a) / 6]2
v = [(8-2) / 6]2
v = [6/6]2
v = [1]2
v = 1

question

Which of these statements regarding time-cost tradeoffs in CPM networks is true?

answer

Crashing shortens the project duration by assigning more resources to one or more of the critical tasks.

question

Which of the following statements regarding Gantt charts is true?

answer

Gantt charts are visual devices that show the duration of activities in a project.

question

__________ is the amount of time an individual activity in a network can be delayed without delaying the entire project.

answer

Slack time

question

The critical path for the network activities shown below is _______ with duration _______.
Activity
Duration
Immediate Predecessors
A
2
B
4
C
6
A,B
D
1
A,B
E
2
B,C,D

answer

B-C-E; 12

question

A project's critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17). What is the standard deviation on the critical path?

answer

1.22

question

An activity has an optimistic time of 11 days, a most likely time of 15 days, and a pessimistic time of 23 days. What is its variance?

answer

4

question

The true statement is that gantt charts are visual devices that show the duration of activities in a project.

answer

Gantt charts are not a precedence diagraming activity or method (such as AON or AOA networks) that create timelines and present the sequence in which activities should be performed. Instead, Gantt charts graphically specify all of the tasks involved in a project and how much time should be spent doing each activity. The four standard spines of Methods, Materials, Manpower, and Machinery are part of cause and effect diagrams and are typically used in the quality control process.
previous

question

The standard deviation on the critical path is 1.22. To calculate the standard deviation you take the square root (?) of the sum of the critical path activity variances. In this case,

answer

Standard deviation = ?.33+.67+.33+.17
Standard deviation = ?1.5
Standard deviation = 1.22

question

The variance for this activity is 4. Variance (v) is calculated by using the following formula: v = [(b-a) / 6]2, where b = pessimistic time estimate (in this case 23) and a = optimistic time estimate (in this case 11). Therefore:

answer

v = [(b-a) / 6]2
v = [(23-11) / 6]2
v = [12 / 6]2
v = [2]2
v = 4
previous

question

In a PERT network, non-critical activities that have little slack need to be monitored closely__________

answer

because near-critical paths could become critical paths with small delays in these activities

question

WBS stands for which of the following project management tools?

answer

Work Breakdown Structure

question

The Beta distribution is used in project management to

answer

Calculate expected activity times

question

The EF of an activity is the:

answer

ES + Activity time